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Q&A In a formal syntax notation, how should I indicate many optional elements?

The problem here is that you are conflating two separate things: the syntax for parameters in a function expression and the list of available parameters. The syntax itself is straightforward enough...

posted 7y ago by Mark Baker‭  ·  last activity 5y ago by System‭

Answer
#4: Attribution notice removed by user avatar System‭ · 2020-01-03T20:41:54Z (almost 5 years ago)
Source: https://writers.stackexchange.com/a/28989
License name: CC BY-SA 3.0
License URL: https://creativecommons.org/licenses/by-sa/3.0/
#3: Attribution notice added by user avatar System‭ · 2019-12-08T06:42:17Z (almost 5 years ago)
Source: https://writers.stackexchange.com/a/28989
License name: CC BY-SA 3.0
License URL: https://creativecommons.org/licenses/by-sa/3.0/
#2: Initial revision by user avatar System‭ · 2019-12-08T06:42:17Z (almost 5 years ago)
The problem here is that you are conflating two separate things: the syntax for parameters in a function expression and the list of available parameters. The syntax itself is straightforward enough:

    CREATE PARSER [schema.]function  
    [WITH [parameter='value' [, parameter='value']+]   
    ];

The list of parameters is:

    LANGUAGE='language'  
    MODE='[FENCED | UNFENCED]'  
    STUFF='anotherParameter'  

Most API documentation separates these two things, which would seem to solve your problem.

BTW, you might point out to your developers that since the parameter values are quoted, the comma is syntactically redundant. Removing it would simplify your diagram and even let you continue to conflate parameter syntax with the list of parameters if you really wanted to.

#1: Imported from external source by user avatar System‭ · 2017-06-29T09:57:39Z (over 7 years ago)
Original score: 3